An iron rod that weighs 24 kg is cut into two pieces so that one of these pieces weighs 16 kg and is 34 m long. If the weight of each piece is proportional to its length, how long is the other piece?

An iron rod that weighs 24 kg is cut into two pieces so that one of these pieces weighs 16 kg and is 34 m long. If the weight of each piece is proportional to its length, how long is the other piece?

(a) 11 m

(b) 17 m

(c) 34 m

(d) 68 m

Answer: 17 m

Solution:

16 kg rod = 34m

24 kg rod = (34×24)/16 = 51m

Length of the other part is = 51-34 = 17m
An iron rod that weighs 24 kg is cut into two pieces so that one of these pieces weighs 16 kg and is 34 m long. If the weight of each piece is proportional to its length, how long is the other piece? An iron rod that weighs 24 kg is cut into two pieces so that one of these pieces weighs 16 kg and is 34 m long. If the weight of each piece is proportional to its length, how long is the other piece? Reviewed by Admin on 9:24 AM Rating: 5

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